2x^2+x-28=42

Solution for 2x^2+x-28=42 equation:

2x^2+x-28=42

We move all terms to the left:

2x^2+x-28-(42)=0

We add all the numbers together, and all the variables

2x^2+x-70=0

a = 2; b = 1; c = -70;
Δ = b2-4ac
Δ = 12-4·2·(-70)
Δ = 561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{561}}{2*2}=\frac{-1-\sqrt{561}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{561}}{2*2}=\frac{-1+\sqrt{561}}{4}
$